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The number (2217)8 is equivalent to





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Solution

(2217)8 =(010010001111)8
Pair of 4 Bits 
1111= F
1000=8
0100=4
(010010001111)=(48F)16


The binary multiplication 00*11 will give





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Solution

0*3=0


The binary equivalent of (234.125)10?





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Solution



Determine the octal equivalent of (432267)10?





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Solution



One Exabyte is equal to …





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Solution



The logic XOR operation of (4AC0)16 and (B53F)16 results





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Solution



Equivalent of the decimal number (25.375)10 in  binary form





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Solution

Decimal to Binary Conversion

? Given: Convert (25.375)10 to binary.

? Step-by-step:

  • Integer Part (25):
    Divide by 2 repeatedly:
    25 ÷ 2 = 12 remainder 1  
    12 ÷ 2 = 6  remainder 0  
    6  ÷ 2 = 3  remainder 0  
    3  ÷ 2 = 1  remainder 1  
    1  ÷ 2 = 0  remainder 1  
          
    Binary: 11001
  • Fractional Part (0.375):
    Multiply by 2 repeatedly:
    0.375 × 2 = 0.75   → 0  
    0.75 × 2  = 1.5    → 1  
    0.5 × 2   = 1.0    → 1  
          
    Binary: .011

✅ Final Binary Answer: (25.375)10 = (11001.011)2



A family has several children. Each boy in this family has as many sisters as brothers, but each girl has twice as many brothers as sisters. How many brothers and sisters are there?





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Solution



A Group of 630 children are seated in n rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible?





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Solution



405 sweets were distributed equally among a group of children such that the number of sweets received by each child is one-fifth of the number of children. The number of children in the group is





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Solution



What is the missing number in the series 4, 7, 11, 18, 29, 47, __________, 123, 199?





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Solution



A bus starts from its depot filled to seating capacity. It stops at a point A where 1/6th of the passengers alight and 10 board the bus. At point B, 1/5th of the passengers alight and 3 board the bus. At point C which is the last stop, all the 55 passengers alight. The capacity of the bus is





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Solution



If all the 6's are replaced by 9's, then the algebraic sum of all the numbers from 1 to 100 (both inclusive)





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Solution



The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively is





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Solution

The first number = (1657 - 6) = 1651

Second number = (2037 - 5) = 2032

Taking the HCF of two numbers 1651, 2032 we get 127.

So, if we divide 1657 and 2037 by 127 we will get remainders 6 and 5 respectively.


Suppose the largest n bit number requires ‘d’ digits in decimal representation. Which of the following relations between ‘n’ and ‘d’ is approximately correct 





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Solution

n bits binary number required d -decimal digits.

So, 10d>2n

Take on both side 

log10(10d)>log10(2n)

d>nlog10(2)


‘Floating point representation' is used to represent





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Solution



Each of A, B and C is a different digit among 1 to 9. How many different values of the sum of A, B and C are possible, if  ABA X AA=ACCA ?





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Solution




Consider the equation (43)= (y3)8 where x and y are unknown. The number of possible solutions is





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Solution



Choose the correct option for the remainder when X = 1! + 2! + 3! + ...........+ 100! is divided by 24





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Solution



Insert the missing number: 16, 33, 65, 131, 261, ?





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Solution



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